I need help please!!
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Answer:
[tex]\frac{1}{x-2}[/tex]
Step-by-step explanation:
Since the denominators of both fractions are common.
Then add the numerators leaving the denominator, that is
= [tex]\frac{4x-3-3x+3}{x^2-2x}[/tex]
= [tex]\frac{x}{x^2-2x}[/tex] ← factor out x from each term in the denominator
= [tex]\frac{x}{x(x-2)}[/tex] ← cancel x on numerator/ denominator
= [tex]\frac{1}{x-2}[/tex]