Answer:
The width of the piece is 11 inches
Step-by-step explanation:
Let
x ----> the length of the rectangular piece of aluminum in inches
y ----> the width of the rectangular piece of aluminum in inches
we know that
The perimeter of the rectangular piece of aluminum is equal to
[tex]P=2(x+y)[/tex]
we have
[tex]P=64\ in[/tex]
so
[tex]64=2(x+y)[/tex]
simplify
[tex]32=x+y[/tex] ----> equation A
[tex]x=y+10[/tex] ----> equation B
Solve the system by substitution
substitute equation B in equation A
[tex]32=y+10+y[/tex]
solve for y
[tex]32=2y+10[/tex]
[tex]2y=32-10[/tex]
[tex]2y=22[/tex]
[tex]y=11[/tex]
therefore
The width of the piece is 11 inches
