Answer:
the minimum radius of the plane path would be 147.45 meters.
Explanation:
given speed of the plane = 100 m/s.
and centripetal acceleration ≤ 6.92×g
we know that centripetal acceleration = [tex]\frac{v^{2}}{r}[/tex]
therefore[tex]\frac{v^{2}}{r}\leq 6.92\times 9.81\\[/tex]
therefore [tex]r\geq \frac{100\times 100}{6.92\times 9.81}[/tex]
therefore r ≥ 147.54 meters
