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What is the Reynolds number for blood leaving the heart through the aorta if the diameter of the aorta is 2.15 cm and the blood has a dynamic viscosity of 2.70 × 10-3 Pa·s, a density of 1050 kg/m3, and travels at a mean fluid velocity of 28.9 cm/s?

Respuesta :

Answer:

Reynolds number will be 2416.3611

Explanation:

We have given diameter of aorta d = 2.15 cm = 0.0215m

Dynamic viscosity of blood [tex]\mu =0.0027Pa-sec[/tex]

Fluid velocity [tex]\v =28.9cm/sec=0.289m/sec[/tex]

Fluid density [tex]\rho =1050kg/m^3[/tex]

We have to find the Reynolds number

We know that  Reynolds number is given by

[tex]R=\frac{\rho vd}{\mu }=\frac{1050\times 0.289\times 0.0215}{0.0027}=2416.3611[/tex]

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