A company that offers tubing trips down a river rents tubes for a person to use for $20 and "cooler" tubes to carry food and water for $12.50. A group spends $270 to rent a total of 15 tubes. How many of each type of tube does the group rent?

Respuesta :

Answer:

The number of river rent tubes are 11 and the number of cooler tubes are 4.

Step-by-step explanation:

Given,

Total number of tubes = 15

Total amount of money spent = $270

Price of river rent tube = $20

Price of cooler tube = $12.50

Solution,

Let the number of river rent tube be x.

And the number of cooler tube be y.

So,

Total number of tubes = The number of river rent tube +  The number of cooler tube

On substituting the values, we get;

[tex]x+y=15\ \ \ \ \ \ equation\ 1[/tex]

Now,

Total amount of money spent = Price of river rent tube X The number of river rent tube + Price of cooler tube X The number of cooler tube

So,

[tex]20x+12.50y=270\ \ \ \ \ \ equation\ 2[/tex]

Now multiplying equation 1 by 20 and then subtract equation 2 from it, we get;

[tex]20(x+y)=20\times15\\20x+20y=300[/tex]

[tex](20x+20y=300) - (20x+12.50y=270)\\\\7.50y=30\\\\y=\frac{30}{7.50} =\frac{300}{75} =4[/tex]

[tex]y=4[/tex]

On substituting the value of y in equation 1, we get the value of x;

[tex]x+y=15\\x+4=15\\x=15-4=11[/tex]

Thus the number of river rent tubes are 11 and the number of cooler tubes are 4.