Answer:
0.958891203 m/s²
Explanation:
N = Weight of crate = 900 N
[tex]\mu[/tex] = Coefficient of friction = 0.25
Force of friction acting on the force applied
[tex]f=\mu N\\\Rightarrow f=0.25\times 900\\\Rightarrow f=225\ N[/tex]
Force used to pull the crate
[tex]F=340cos 23\\\Rightarrow F=312.97165\ N[/tex]
The net force is
[tex]F_n=F-f\\\Rightarrow F_n=312.97167-225\\\Rightarrow F_n=87.97167\ N[/tex]
Acceleration is given by
[tex]a=\frac{F_n}{m}\\\Rightarrow a=\dfrac{87.97167}{\dfrac{900}{9.81}}\\\Rightarrow a=0.958891203\ m/s^2[/tex]
The magnitude of the acceleration of the crate is 0.958891203 m/s²
