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Three liquids that will not mix are poured into a cylindrical container. The volumes and densities of the liquids are
0.574 L, 2.50 g/cm3;
0.445 L, 1.04 g/cm3; and
0.498 L, 0.659 g/cm3.
What is the force on the bottom of the container due to these liquids?

Respuesta :

Force on the bottom of the container due to liquids is 21.86 N

Explanation:

Total force is total weight of liquid.

Weight = Mass x Acceleration due to gravity

Liquid 1

        Volume = 0.574 L = 574 cm³

        Density = 2.50 g/cm³

        Mass = 574 x 2.50 = 1435 g = 1.435 kg

Liquid 2

        Volume = 0.445 L = 445 cm³

        Density = 1.04 g/cm³

        Mass = 445 x 1.04 = 462.8 g = 0.463 kg

Liquid 3

        Volume = 0.498 L = 498 cm³

        Density = 0.659 g/cm³

        Mass = 498 x 0.659 = 328.18 g = 0.33 kg

Total mass of liquids = 1.435 + 0.463 + 0.33 = 2.228 kg

Weight = Mass x Acceleration due to gravity

Weight = 2.228 x 9.81

Weight = 2.228 x 9.81 = 21.86 N

Force on the bottom of the container due to these liquids = 21.86 N

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