A plant worker accidentally breathes some stored gaseous tritium, a beta emitter with maximum particle energy of 0.0186 MeV. The energy absorbed by the lungs, which have a total weight of l kg, is 4 x 10^-3 J. How many milli-rems dose equivalent was received?

Respuesta :

Answer:

400 milli-rems

Solution:

As per the question;

Maximum energy of particle, [tex]E_{m} = 0.0186\ MeV[/tex]

Weight, w = 1 kg

Energy absorbed, E = [tex]4\times 10^{- 3}\ J[/tex]

Now,

Equivalent dose is given by:

[tex]D_{eq} = \frac{E}{w}  =\frac{4\times 10^{- 3}}{1} = 4\times 10^{- 3}\ J/kg[/tex]

1 Gy = 1 J/kg

Also,

1 Gy = [tex]1\times 10^{5}\ milli-rems[/tex]

Therefore,

Dose equivalent in milli-rems is given by:

[tex]D_{eq} = 4\times 10^{- 3}\times 1\times 10^{5} = 400\ milli-rems[/tex]