Answer:
IQR = 6
Step-by-step explanation:
Given:
The given set of data is:
40 41 42 43 44 45 46 47 48 49 50
Number of terms, [tex]n=11[/tex]
Therefore, the median is given as [tex](\frac{n+1}{2})^{th}[/tex] term which is the sixth term. Median = 45
(40 41 42 43 44) 45 (46 47 48 49 50 )
Now, we find the median of the lower half ([tex]Q_1[/tex]) and upper half ([tex]Q_3[/tex])of the data that are before and after the median.
The lower half of the data has the values 40 41 42 43 44.
Number of terms are 5. So, median is the third term which is, [tex]Q_1=42[/tex]
The upper half of the data has the values 46 47 48 49 50.
Number of terms are 5. So, median is the third term which is, [tex]Q_3=48[/tex]
Now, IQR is given as the difference of upper half median and lower half median.
[tex]IQR=Q_3-Q_1\\IQR=48-42=6[/tex]
Answer:
6
Step-by-step explanation:
40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50
Median: 45
Lower quartile: 42
Upper quartile: 48
Interquartile range: 48 - 42 = 6
