Answer:
The volume of 2M stock solution added = 2 mL
The volume of water = 198 mL
Explanation:
Considering
[tex]Molarity_{working\ solution}\times Volume_{working\ solution}=Molarity_{stock\ solution}\times Volume_{stock\ solution}[/tex]
Given that:
[tex]Molarity_{working\ solution}=20\ mM=0.02\ M[/tex]
[tex]Volume_{working\ solution}=200\ mL[/tex]
[tex]Volume_{stock\ solution}=?[/tex]
[tex]Molarity_{stock\ solution}=2\ M[/tex]
So,
[tex]0.02\ M\times 200\ mL=2\ M\times Volume_{stock\ solution}[/tex]
[tex]Volume_{stock\ solution}=\frac{0.02\times 200}{2}\ mL=2\ mL[/tex]
The volume of 2M stock solution added = 2 mL
The volume of water = 200 - 2 mL = 198 mL
