Answer:
the 19th term of the arithmetic sequence is 73.
Step-by-step explanation:
Given:
The arithmetic sequence whose common difference is
[tex]d=4[/tex]
And first term is
[tex]a=1[/tex]
Find the 19th term of the arithmetic sequence
[tex]n=19[/tex]
Now we know that,
[tex]a_{n}=a+(n-1)d[/tex]
Put all the value in above AP.
[tex]a_{19}= 1+(19-1)4[/tex]
[tex]a_{19}= 1+18\times 4[/tex]
[tex]a_{19}= 1+72[/tex]
[tex]a_{19}= 73[/tex]
So, [tex]19_{th}[/tex] term of the sequence is 73.
