Answer:
[tex]m\angle PQW=30^o[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
[tex]m\angle PQR=m\angle PQW+m\angle WQR[/tex] ---> by addition angle postulate
substitute the given values
[tex]16x=3x+130\o[/tex]
solve for x
[tex]16x-3x=130^o[/tex]
[tex]13x=130^o[/tex]
[tex]x=10^o[/tex]
Find the measure of angle PQW
[tex]m\angle PQW=3x[/tex]
substitute the value of x
[tex]m\angle PQW=3(10^o)=30^o[/tex]