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An air bubble is expelled by an underwater diver at a depth of 22.3 m. As the bubble rises to the surface, the pressure decreases and the volume of the bubble therefore increases. The temperature of the water is constant. Find the final volume of the bubble if its initial volume is 10.5 cm3.

Respuesta :

Answer:s

V₂ = 27.33 cm³

Explanation:

given,

depth of the air bubble under water = 22.3 m

initial volume of the bubble = 10.5 cm³

final volume of the bubble = ?

Pressure under water increase

P₁ = P₂ + ρ g h

 P₂= 10⁵ Pa

g is the acceleration due to gravity, g = 9.8 m/s²

Using idea gas law

P₁ V₁ = P₂ V₂

V₂ = [tex]\dfrac{P_1V_1}{P_2}[/tex]

V₂ = [tex]\dfrac{(10^5 +1000 \times 9.8 \times 22.3)\times 10.5}{10^5}[/tex]

 V₂ = 27.33 cm³

final volume of the bubble will be equal to  V₂ = 27.33 cm³

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