The orbital period is 3770 s
Explanation:
The linear speed of the moon in its orbit around the planet is equal to the ratio between the lenght of the circumference of the orbit and the period of revolution:
[tex]v=\frac{2\pi r}{T}[/tex]
where
v is the linear speed
r is the radius of the orbit
T is the orbital period
In this problem, we have:
[tex]v=9.0 \cdot 10^3 m/s[/tex] is the speed
[tex]r=5.4\cdot 10^6 m[/tex] is the orbital radius
Therefore, we can re-arrange the equation to find the period, T:
[tex]T=\frac{2\pi r}{v}=\frac{2\pi (5.4\cdot 10^6)}{9.0\cdot 10^3}=3770 s[/tex]
Learn more about circular motion:
brainly.com/question/2562955
brainly.com/question/6372960
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