A single alkyl bromide reactant theoretically yields either of the given products, depending on the reaction conditions. Draw the structure of the alkyl bromide compound.

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Answer:

[tex]H_{3}C[/tex]--[tex]H_{3}C[/tex]--[tex]CH_{3}[/tex]--Br--[tex]CH_{3}[/tex]

Explanation:

The steps involved in predicting the structure of the alkyl bromide compound are outlined below.

1) An examination of the product shows that the product could only be formed by a substitution reaction.

2) The structure of the alkyl bromide compound can be then predicted by replacing the methoxide group in the product after the substitution of bromine atom. This is because the methoxide ion acts as a strong nucleophile.

Therefore, by consideration the reaction mechanisms of reactions 1 and 2, it can be predicted that the structure of the alkyl bromide compound is [tex]H_{3}C[/tex]--[tex]H_{3}C[/tex]--[tex]CH_{3}[/tex]--Br--[tex]CH_{3}[/tex]. A pictorial diagram of the alkyl bromide compound is also attached.

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Alkyl bromide is formed when bromide replaced hydrogen in alkane.

Structure of the alkyl bromide compound

Alkyl halides are also called haloalkanes. Alkyl halides are compounds in which hydrogen atoms in an alkane have been replaced by halogen atoms such as fluorine, chlorine, bromine or iodine so we can conclude that alkyl bromide is formed when bromide replaced hydrogen in alkane.

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