Answer:
The speed in m/s at which water is ejected from the hole is 17.98 m/s.
Explanation:
Given that,
Height of tank[tex]h_{c}= 20.0\ m[/tex]
Height [tex]h=16.5\ m[/tex]
Flow rate [tex]Q= 2.40\times10^{-3}\ m^3/min[/tex]
We need to calculate the speed in m/s at which water is ejected from the hole
Using formula of speed
[tex]v=\sqrt{2gh}[/tex]
Where, v = speed
g = acceleration due to gravity
h = height
Put the value into the formula
[tex]v=\sqrt{2\times9.8\times16.5}[/tex]
[tex]v=17.98\ m/s[/tex]
Hence, The speed in m/s at which water is ejected from the hole is 17.98 m/s.
