Answer:
The magnitude of the acceleration of the box is 1.664 m/s².
Explanation:
Given that,
Mass of box = 3.00 kg
Angle = 34.5°
Distance = 2.00 m
Time = 1.55 s
We need to calculate the magnitude of the acceleration of the box
Using equation of motion
[tex]s = ut+\dfrac{1}{2}at^2[/tex]
[tex]a=\dfrac{2s}{t^2}[/tex]
Where, s = distance
t = time
a = acceleration
Put the value into the formula
[tex]a=\dfrac{2\times2.00}{1.55^2}[/tex]
[tex]a=1.664\ m/s^2[/tex]
Hence, The magnitude of the acceleration of the box is 1.664 m/s².
