Answer:
[tex]-3.25\times 10^6 J[/tex]
Explanation:
We are given that
Work done by the system=[tex]4.5\times 10^5[/tex] J
Heat transfer into the system=[tex]U_1=3.2\times 10^6[/tex] J
Heat transfer to the environment=[tex]U_2=6\times 10^6[/tex] J
We have to find the change in internal energy
By first law of thermodynamics
[tex]\Delta Q=\Delta U+w[/tex]
[tex]\Delta Q=U_1-U_2=3.2\times 10^6-6\times 10^6=-2.8\times 10^6J[/tex]
Substitute the values then we get
[tex]-2.8\times 10^6=\Delta U+4.5\times 10^5[/tex]
[tex]\Delta U=-2.8\times 10^6-4.5\times 10^5=-28\times 10^5-4.5\times 10^5=-32.5\times 10^5=-3.25\times 10^6 J[/tex]
Hence, the change in internal energy =[tex]-3.25\times 10^6 J[/tex]
