Answer:
B = 0.0087 T
Explanation:
given,
Length of solenoid (L)= 83 cm = 0.83 m
radius of the solenoid (r)= 2.10 cm = 0.021 m
number of turns (N)= 1600 turns
current (I)= 3.60 A
Using magnetic field formula
[tex]B = \dfrac{\mu_0Ni}{L}[/tex]
[tex]B = \dfrac{4 \pi \times 10^{-7} \times 1600 \times 3.6}{0.83}[/tex]
B = 0.0087 T
the magnitude of magnetic field inside the solenoid is equal to B = 0.0087 T
