Respuesta :
Answer:
0.528 Molar is the molarity of the solution.
Explanation:
Molality of the solution = 0.0480 molal
Density of the solution = d = 1.10 g/mL
0.0480 moles of LiF was present in 1 kg solvent.
Mass of 0.0480 moles of LiF = 0.0480 mol × 26 g/mol = 1.248 g
Mass of the solution (m)= 1 kg (solvent) + 1.248 g(solute)
m = 1000 g + 1.248 g = 1001.248 g
Volume of the solution = V = ?
[tex]V=\frac{Mass}{density}=\frac{m}{V}[/tex]
[tex]V=\frac{1001.248 g}{1.10 g/mL}=910.2254 mL[/tex]
V = 910.2254 mL = 0.9102254 L
Molarity of the solution is the moles of compound in 1 Liter solutions.
[tex]Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}[/tex]
[tex]Molarity=\frac{1.248 g}{26 g/mol\times 0.9102254 L}=0.528 mol/L[/tex]
0.528 Molar is the molarity of the solution.
The molarity of the solution is 0.528 mol/l.
The correct option is (C).
What is molarity?
The molarity of any solution is the number of moles per liter of the solution.
Given,
The molality of the solution is 0.0480 m Lif
The density of the solution is 1.10 g/ml
Step 1: 0.0480 moles of LiF were present in 1 kg solvent.
Mass of 0.0480 moles of LiF = 0.0480 mol × 26 g/mol = 1.248 g
Mass of the solution (m)= 1 kg (solvent) + 1.248 g(solute)
m = 1000 g + 1.248 g = 1001.248 g
Step 2: Find the volume of the solution
[tex]\bold{Volume = \dfrac{mass}{Density} =\dfrac{1001.248 g}{1.10 g/ml} = 910.2254\; ml}[/tex]
Step 3: Calculating the molarity
[tex]\bold{Molarity =\dfrac{mass\;of \;compound}{Molar\;mass\;of\;compound\times Volume } }[/tex]
[tex]\bold{Molarity =\dfrac{1.248 g}{26\;g/mol\times 910.225 ml } = 0.528\; mol/l }[/tex]
Thus, the molarity of the solution is 0.528 mol/l.
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