One brand of vinegar has a pH of 4.5. Another brand has a pH of 5.0. The equation for the pH of a substance is pH = –log[H+], where H+ is the concentration of hydrogen ions. What is the approximate difference in the concentration of hydrogen ions between the two brands of vinegar?

A. 2.2 x10^-5
B. 3.2x10^-1
C. 3.2x10^1
D.6.8x10^4

First brand of vinegar:
4.5=-log(H1)
Second brand:
5=-log(H2)
[tex]4.5 = log (H1)^{-1} 5=log(H2) ^{-1} 1/H1= 10^{4.5} , 1/H2=10 ^{5} H1=10 ^{-4.5}, H2=10 ^{-5} [/tex]
We have used logarithmic rules.
[tex] 10^{-4.5} - 10 ^{5}=10^{1/2}*10^{-5}-10^{-5}= \sqrt{10}*10^{-5}-10^{-5} [/tex]
Finally:
[tex]3.2 * 10^{-5}- 10^{-5} =2.2 * 10^{-5} [/tex]
Answer:A) 2.2 x 10^-5

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sheenuvt12 sheenuvt12 · Answer 2 · 2022-06-07T00:11:50+02:00

The approximate difference in the concentration of hydrogen ions between the two brands of vinegar is 2.2 x [tex]10^{-5}[/tex].

The correct option is (A).

What is concentration of Hydrogen ion?

The concentration of hydrogen ions in a solution expressed usually in moles per liter or in pH units and used as a measure of the acidity of the solution indicator dyes for narrow ranges of hydrogen-ion concentration.

Given: pH = –log[H+], pH=0.5

[H+] ions in first brand:

4.5 = -log([H+])

[H+] = [tex]10^{-4.5\\}[/tex]

[H+] ions in second brand:

5 = -log[H+]

[H+] = [tex]10^{-5\\}[/tex]

The difference in the concentration of hydrogen ions between the two brands of vinegar

= [tex]10^{-4.5\\}[/tex] - [tex]10^{-5\\}[/tex]

= 2.2 x [tex]10^{-5}[/tex]

Hence, the approximate difference in the concentration of hydrogen ions between the two brands of vinegar is 2.2 x [tex]10^{-5}[/tex]

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