Answer : The mass lost would be, [tex]8.71\times 10^{-10}Kg[/tex]
Solution : Given,
Energy released = [tex]7.84\times 10^{7}J=7.84\times 10^{7}\text{ Kg }m^2/s^2[/tex]
[tex](1J=1\text{ Kg }m^2/s^2)[/tex]
Speed of light 'c' = [tex]3\times 10^{8}m/s[/tex]
Formula used :
[tex]E=m\times c^2[/tex]
where,
E = energy
m = mass
c = speed of light
Now put all the given values in the above formula, we get
[tex]7.84\times 10^{7}\text{ Kg }m^2/s^2=m\times (3\times 10^{8}m/s)^2[/tex]
[tex]m=8.71\times 10^{-10}Kg[/tex]
Therefore, the mass lost would be, [tex]8.71\times 10^{-10}Kg[/tex]
