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A 43-N crate is suspended from the left end of a plank. The plank weighs 21 N, but it is not uniform, so its center of gravity does not lie halfway between the two ends. The system is balanced by a support that is 0.30 m from the left end of the plank. How far to the right of the support is the plank

Respuesta :

davidlcastiblanco

Answer:

[tex]d_{2}=0.585m[/tex]

Explanation:

The torque is the force by the distance so to determinate that both torque are the same magnitude so

[tex]T_{1}-T_{2}=0[/tex]

[tex]T_{1}=T_{2}[/tex]

[tex]F_{1}*d_{1}=F_{2}*d_{2}[/tex]

[tex]43N*0.30m=21N*d_{2}[/tex]

Solve to d2

[tex]d_{2}=\frac{41N*0.30m}{21N}[/tex]

[tex]d_{2}=0.585m[/tex]

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