Answer:
Q = 30750 j
Explanation:
Given data:
Mass of block = 50 g
Initial temperature = -150.0 °C
Final temperature = 150.0 °C
Amount of heat required = ?
Solution:
Specific heat capacity of ice = 2.05 j/g. °C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T₂- T₁
ΔT = 150 - (-150)
ΔT = 300 °C
Q = m.c. ΔT
Q = 50 g × 2.05 j/g. °C × 300 °C
Q = 30750 j
