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y=x^2 2y+6=2(x+3) If (x,y) is a solution of the system of equations above and x>0, what is the value of xy

Respuesta :

Answer:x,=√1. Y=1

Step-by-step explanation:

Answer:

a.) 1

Explanation:

y = x2 -------- eqn(1)

2y +6 = 2(x +3) ------- eqn(2)

substitute eqn(1) into eqn(2)

2(x2) + 6 = 2x + 6

2x2 - 2x + 6 - 6 = 0

2x2 - 2x = 0

divide through by 2

x2 - x = 0  

x2 = x

x = 1

Substitute x = 1 into eqn(1)

y = (1)2

y = 1

xy = 1 x 1

= 1

Ans A