Answer:
10 liters of 40% solution
10 liters of 10% solution
Step-by-step explanation:
Let's say x is the liters of 40% solution, and y is the liters of 10% solution.
Write equations using the volume and amount of salt:
x + y = 20
0.40 x + 0.10 y = 0.25 (x + y)
Solve the system of equations.
0.40 x + 0.10 (20 − x) = 0.25 (x + 20 − x)
0.40 x + 2 − 0.10 x = 0.25 (20)
0.30 x + 2 = 5
0.30 x = 3
x = 10
y = 10
You need 10 liters of 40% solution and 10 liters of 10% solution.
Joy needs 10 liters of 40% solution and 10 liters of 10% solution to make 20 liters of a 25% saline solution
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
Molarity shows the number of moles of solute in every 1 liter of solution.
[tex] \large {\boxed {\bold {M ~ = ~ \frac {n} {V}}} [/tex]
Molarity of a mixture of 2 solutions can use the formula.
Vc Mc = V1. M1 + V2. M2
[tex]\rm Mc=\dfrac{(M1\times V1)+(M2\times V2)}{Vc}[/tex]
Vc = mixed volume
Mc = mixed volume
V1 = volume of solution 1
M1 = Molarity of solution1
V2 = volume of solution 2
M2 = Molarity of solution 2
Joy is preparing 20 liters of a 25% saline solution. She has only a 40% solution and a 10% solution in her lab, then :
Mc = 25%
Vc = 20 L
M1 = 40%
M2 = 10%
Vi+V2 = 20 L ⇒ V2= 20 - V1
[tex]\rm 25\%=\dfrac{(40\%\times V1)+(10\%\times (20-V1))}{20}\\\\5=0.4V1+0.1(20-V1)\\\\5=0.4V1+2-0.1V1\\\\3=0.3V1\\\\V1=10\:L\\\\V2=20-10=10\:L[/tex]
Calculate the molarity of a solution
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