Until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track, it can speed up
to 45 m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train?
m/s4

Respuesta :

Answer:

The acceleration of the train is 5 m/s².

Explanation:

Acceleration is the change in velocity over a given time interval.

Therefore, acceleration is given as:

[tex]a=\frac{v_{f}-v_{i}}{\Delta t}[/tex]

Where, [tex]v_{i}\textrm{ and }v_{f}[/tex] are initial and final velocities and [tex]\Delta t[/tex] is the time interval.

Here, [tex]v_{i}=5\textrm{ m/s},v_{f}=45\textrm{ m/s},\Delta t=8\textrm{ s}[/tex]

This gives,

[tex]a=\frac{45-5}{8}=\frac{40}{8}=5\textrm{ }m/s^{2}[/tex]

Therefore, the acceleration of the train is 5 m/s².