Answer:
The distance between them, x = 5809.47 m
Explanation:
Given,
The average weight of a human, w = 600 N
The charge carried by the humans, q = 1.5 C
If 600 N of force acts between two opposite charges, the distance between the charges can be derived from the Coulomb's laws of force,
[tex]F=\frac{1}{4\pi\epsilon_{0}}\frac{qq}{x^{2}}[/tex]
Where,
[tex]\frac{1}{4\pi\epsilon_{0}}[/tex] = 9 x 10⁹ N m² C⁻²
Therefore
x² = 9 x 10⁹ X 1.5² / 600
= 33750000
x = 5809.46 m
Hence, the distance between the humans should be, x = 5809.47 m
2 humans with an excess charge of 1.5 C must be 5.81 km apart to experience an electric force of 600 N.
Coulomb's law states that like charges repel and opposite charges attract, with a force proportional to the product of the charges and inversely proportional to the square of the distance between them.
2 generic humans carry 1.5 C excess charge, the distance between them for the attraction force to be 600 N is:
F = k × q₁ × q₂ / r²
600 N = (8.99 × 10⁹ N.m²/C²) × 1.5 C × 1.5 C / r²
r = 5.81 × 10³ m = 5.81 km
where,
2 humans with an excess charge of 1.5 C must be 5.81 km apart to experience an electric force of 600 N.
Learn more about Coulomb's law here: https://brainly.com/question/66110
