*Due midnight tonight. Plz help*
Andrea and Carlos left the airport at the same time. Andrea flew at 180 mph on a course with a bearing of 80°​,and Carlos flew at 230 mph on a course with a bearing of 210°. Find the approximate distance between them after 4 hours.​

Due midnight tonight Plz helpAndrea and Carlos left the airport at the same time Andrea flew at 180 mph on a course with a bearing of 80and Carlos flew at 230 m class=

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lucic

The distance between them after 4 hours is 1488.75 miles.

Step-by-step explanation:

In this question apply the law of cosine/The Cosine Rule which states that :

c²=a²+b²-2abcosC where a, b and c are sides of the triangle and C is the angle between the two points.

In this case, the points will be Carlos location and Andrea location , where the angle between their locations is , ∠C 130° ,(210°-80°). Then a will be Andrea's speed, 180 mph and b will be Carlos's speed 230 mph. Finding the distance between then, c, after 4 hours will be;

c²=a²+b²-2abcosC   where a=180, b=230, ∠C=130°

c=√ (a²+b²-2abcosC)

c=√(180²+230²-2×180×230×cos(130°) )

c=372.19 miles

After 4 hours, the distance will be : 4×372.19 = 1488.75 miles

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Bearing : https://brainly.com/question/13536178

Keyword : Distance, bearing

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