Answer:
B-) 0.2857
Step-by-step explanation:
So to be shipped all of the toys, toys need to be not faulty. This means that we will think about the undefective ones.
We have :
2 defective toys
5 undefective toys
To be shipped all of the toys must be undefective.
We will have to choose undefective ones from all the toys, 3 times:
Undefective ones Undefective ones Undefective ones
--------------------------- . ----------------------------- . --------------------------
All the toys All the toys All the toys
> 5/7 . 4/6 . 3/5
>0.28571428571
So, the answer is B-) 0.2857
I hope it will be understood.
If I have any inaccuracies please let me know.
Have a nice day and never stop questioning!
Using the hypergeometric distribution, it is found that the probability that it will be shipped is:
b) 0.2857
The toys are chosen without replacement, which is the reason why the hypergeometric distribution is used.
Hypergeometric distribution:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
In this problem:
It will be shipped if none are defective, thus, the probability is P(X = 0).
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 0) = h(0,7,3,2) = \frac{C_{2,0}C_{5,3}}{C_{7,3}} = 0.2857[/tex]
The probability is:
b) 0.2857
A similar problem is given at https://brainly.com/question/8174838
