Ask Your Teacher Sodium hydroxide solution is usually standardized by titrating a pure sample of potassium hydrogen phthalate (KHC8H4O4, often abbreviated KHP), an acid with one acidic hydrogen and a molar mass of 204.220 g/mol. It takes 36.01 mL of a sodium hydroxide solution to titrate a 0.1182-g sample of KHP. What is the molarity of the sodium hydroxide

Respuesta :

Answer:

0.0161 M

Explanation:

Moles of KHP :

Given, Mass of KHP = 0.1182 g  

Molar mass of KHP = 204.22 g/mol

The formula for the calculation of moles is shown below:

[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]

Thus,

[tex]Moles= \frac{0.1182\ g}{204.22\ g/mol}[/tex]

[tex]Moles\= 5.7879\times 10^{-4}\ mol[/tex]

According to the reaction shown below:

KHP + NaOH ⇒ KNaP + H₂O

1 mole of KHP reacts with 1 mole of NaOH

So,

[tex]5.7879\times 10^{-4}\ mol[/tex] of KHP reacts with [tex]5.7879\times 10^{-4}\ mol[/tex] of NaOH

Moles of NaOH = [tex]5.7879\times 10^{-4}\ mol[/tex]

Volume = 36.01 mL = 0.03601 L ( 1 mL = 0.001 L)

[tex]Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}[/tex]

[tex]Molarity_{NaOH}=\frac{5.7879\times 10^{-4}}{0.03601 L}[/tex]

[tex]Molarity_{NaOH}=0.0161\ M[/tex]