Answer:
Step-by-step explanation:
This problem belong to a normal distribution probability.
Mean = 63.6
Standard Deviation = 2.5.
We have to find the probability of a height greater than 63.0.
Due to the normal probability, we need to find the Z score first:
[tex]Z=\frac{x-u}{o}[/tex]; where x is the height, u is the mean, and o is the standard deviation.
[tex]Z=\frac{63-63.6}{2.5} \\Z= -0.24[/tex]
Once we have our Z score, we find the probability with the z-table (attached). So, for a z score of -0.24 we have a probability of 0.42.
But, the problem is asking for height greater than 63.0, this mean that we have to subtract 0.42 from 1, giving as result 0.58, which means a 58% of probability,
