Respuesta :
Answer:
3NaOH(aq) + FeBr₃(aq) → 3NaBr(aq) + Fe(OH)₃ (s)
Explanation:
When aqueous sodium hydroxide react with the aqueous iron(III) bromide it form aqueous sodium bromide and solid iron (III) hydroxide. The reaction is given below:
Chemical equation:
NaOH+ FeBr₃ → NaBr + Fe(OH)₃
Balance Chemical equation:
3NaOH(aq) + FeBr₃(aq) → 3NaBr(aq) + Fe(OH)₃ (s)
The balanced chemical equation for the reaction between aqueous NaOH and FeBr₃ is:
3NaOH(aq) + FeBr₃(aq) → 3NaBr(aq) + Fe(OH)₃(s)
When aqueous NaOH and FeBr₃ react, the products obtained are: aqueous NaBr and solid Fe(OH)₃
The equation for the reaction is given below:
NaOH(aq) + FeBr₃(aq) → NaBr(aq) + Fe(OH)₃(s)
The above equation can be balance as follow:
NaOH(aq) + FeBr₃(aq) → NaBr(aq) +
Fe(OH)₃(s)
There are 3 atoms of Br on the left side and 1 atom on the right side. It can be balance by writing 3 before NaBr as shown below:
NaOH(aq) + FeBr₃(aq) → 3NaBr(aq) + Fe(OH)₃(s)
There are 3 atoms of Na on the right side and 1 atom on the left side. It can be balance by writing 3 before NaOH as shown below:
3NaOH(aq) + FeBr₃(aq) → 3NaBr(aq) + Fe(OH)₃(s)
Now, the equation is balanced.
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