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Answer:

3NaOH(aq) + FeBr₃(aq)  →  3NaBr(aq) + Fe(OH)₃ (s)

Explanation:

When aqueous sodium hydroxide react with the aqueous iron(III) bromide it form aqueous sodium bromide and solid iron (III) hydroxide. The reaction is given below:

Chemical equation:

NaOH+ FeBr₃ →  NaBr + Fe(OH)₃

Balance Chemical equation:

3NaOH(aq) + FeBr₃(aq)  →  3NaBr(aq) + Fe(OH)₃ (s)

The balanced chemical equation for the reaction between aqueous NaOH and FeBr₃ is:

3NaOH(aq) + FeBr₃(aq) → 3NaBr(aq) + Fe(OH)₃(s)

When aqueous NaOH and FeBr₃ react, the products obtained are: aqueous NaBr and solid Fe(OH)₃

The equation for the reaction is given below:

NaOH(aq) + FeBr₃(aq) → NaBr(aq) + Fe(OH)₃(s)

The above equation can be balance as follow:

NaOH(aq) + FeBr₃(aq) → NaBr(aq) +

Fe(OH)₃(s)

There are 3 atoms of Br on the left side and 1 atom on the right side. It can be balance by writing 3 before NaBr as shown below:

NaOH(aq) + FeBr₃(aq) → 3NaBr(aq) + Fe(OH)₃(s)

There are 3 atoms of Na on the right side and 1 atom on the left side. It can be balance by writing 3 before NaOH as shown below:

3NaOH(aq) + FeBr₃(aq) → 3NaBr(aq) + Fe(OH)₃(s)

Now, the equation is balanced.

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