Proof:
Given [tex]3(x+1)=7(x-2)-3[/tex]
To prove that the solution of [tex]3(x+1)=7(x-2)-3 [/tex] is 5,
[tex]3(x+1)=7(x-2)-3[/tex]
On taking off the brackets we get,
[tex]3x+3=7x-14-3[/tex]
On grouping the x terms together,
[tex]7x-3x=14+3+3[/tex]
On solving we get,
[tex]4x=20[/tex]
[tex]x=\frac{20}{4}[/tex]
On dividing 20 by 4,
[tex]x=5[/tex]
[tex]\Rightarrow[/tex] Hence proved that the solution for [tex]\bold3(x+1)=7(x-2)-3\bold[/tex] is 5.
