Answer:
The distance is 1500m
Step-by-step explanation:
Data:
V1= 250 m/s
t1= x
V2=300 m/s
t2= x-1
1. We use the speed formula
First Speed = Distance/time
250 m/s = d/t
t=d/250m/s
2. We use the speed formula
Second Speed = Distance/time
300m/s = d/t-1
t-1 = d/300m/s
t = (d/300 m/s) +1
3. we match the variables
t=t
[tex]\frac{d}{250}[/tex] = [tex]\frac{d}{300}[/tex] +1
[tex]\frac{d}{250}[/tex] =[tex]\frac{d+300}{300}[/tex]
d(300) = d+300(250)
300d = 250d+75000
300d-250d=75000
50d=75000
d= [tex]\frac{75000}{50}[/tex]
d= 1500 m
The average speed is the total distance divided by the total time, therefore,
total distance is given by the product of average speed and time.
Reasons:
Let, x represent the distance he was running, and let t, represent the time
it takes to finish the distance at 350 m/min
Therefore;
Distance, x = 350 × t
At 250 m/min, we have;
x = 250 × (t + 1)
Where;
t + 1 = 1 minutes extra needed to complete the distance at the lower speed
Which, by substitution property, gives;
350 × t = 250 × (t + 1)
350·t = 250·t + 250
100·t = 250
t = 250 ÷ 100 = 2.5
t = 2.5 minutes
Therefore;
x = 350 × 2.5 = 875
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