Answer:
0.3397
Step-by-step explanation:
Based on a survey assume that 36% of consumers are comfortable having drones deliver their purchases. Then
- the probability that a consumer is comfortable with the delivery of the drones is [tex]p=0.36;[/tex]
- the probability that a consumer is not comfortable with the delivery of the drones is [tex]q=1-p=1-0.36=0.64.[/tex]
Suppose that we want to find the probability that when five consumers are randomly selected exactly two of them are comfortable with the delivery by drones.
Hence,
[tex]n=5\\ \\x=2[/tex]
and the probability is
[tex]C^5_2p^2q^{5-2}=\dfrac{5!}{2!(5-2)!}(0.36)^2(0.64)^3=10\cdot (0.36)^2(0.64)^3\approx 0.3397[/tex]
