Answer:
[tex]56\div 8=7[/tex]
Step-by-step explanation:
The relationship of division and subtraction:
If [tex]a\div b=c[/tex] then [tex]a-bc=0[/tex] (Definition 1)
The given equation is
[tex]56\div 8=7[/tex]
We need to prove this by subtraction.
Let [tex]56\div 8=x[/tex]
Here, a= 56 is dividend, b=8 is divisor and c=7 is quotient.
[tex]56-8=48[/tex] (1st time)
[tex]48-8=40[/tex] (2nd time)
[tex]40-8=32[/tex] (3rd time)
[tex]32-8=24[/tex] (4th time)
[tex]24-8=16[/tex] (5th time)
[tex]16-8=8[/tex] (6th time)
[tex]8-8=0[/tex] (7th time)
It means we need to subtract 8 (total 7 times) from 56 to get 0.
[tex]56-8\times 7=0[/tex]
Using definition (1) , we get
[tex]56\div 8=7[/tex]
Hence proved.
