Respuesta :

Since

[tex]f(x)=3x^2+3\sqrt{x}+3x[/tex]

the domain of f(x) is the set of non-negative integers, because we can't feed a square root with negative inputs. So, you couldn't comput f(-9)

Unless you're allowed to use complex numbers, in that case we have

[tex]f(-9)=3\cdot (-9)^2+3\sqrt{-9}+3\cdot (-9)=3\cdot 81+3\cdot (9i)-27[/tex]

Which evaluates to

[tex]243+27i-27=216+9i[/tex]

abidemiokin

The value of the function if x is -9 is 9i + 216

Functions and values

Given the function expressed as:

[tex]f(x) = 3x^2+ 3x^{(1/2)} + 3x[/tex]

If the value of x is -9, hence the function will become:

[tex]f(x) = 3(-9)^2+ 3(-9)^{(1/2)} + 3(-9)\\f(x)=3(81)+3(3i)-27\\[/tex]

Simplify the result to have:

[tex]f(x) = 243 + 9i -27\\f(x) = 9i + 216[/tex]

Hence the value of the function if x is -9 is 9i + 216

Learn more on function here: https://brainly.com/question/17043948

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