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A mass is dropped (i.e., initial v=0) from the top of a tall building at a height of 300 m. If we neglect air friction, find the velocity of the object when it hits the ground (m/s). g = 9.8 m/s^2

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kmag1991

Answer:

The velocity of the object right before impact is 76.68 m/s.

Explanation:

According to the formula for the velocity of an object free falling, it is the squared root of 2 times gravity times the height. Neglecting the friction that could be caused by the air. The formula used is below:

v=\sqrt{2.g.h}[/tex]

v=\sqrt{2.9,8.3}[/tex]

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