Answer:
number of full period per major division = 1
Explanation:
given,
20 MHz oscilloscope
for a 5 MHz signal
time period of signal
[tex]T = \dfrac{1}{\mu}[/tex]
[tex]T = \dfrac{1}{5 \times 10^{6}}[/tex]
T = 0.2 × 10⁻⁶ s
T = 0.2 μs
a major division = 0.2 μs
number of full period per major division =[tex]\dfrac{0.2}{0.2}[/tex]
number of full period per major division = 1