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A person is trying to judge whether a picture (mass = 1.14 kg) is properly positioned by temporarily pressing it against a wall. The pressing force is perpendicular to the wall. The coefficient of static friction between the picture and the wall is 0.720. What is the minimum amount of pressing force that must be used?

Respuesta :

Answer:15.51 N

Explanation:

Given

mass of object=1.14 kg

coefficient of static friction [tex]\mu =0.720[/tex]

friction force will balance weight of object

weight[tex]=m\times g=1.14\times 9.8=11.172 N[/tex]

Friction Force[tex]=\mu N[/tex]

and N=F

[tex]\mu F=11.172[/tex]

[tex]F=\frac{11.172}{0.720}=15.51 N[/tex]

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