Answer:
D) The equilibrium lies far to the left
Explanation:
According to the law of mass action, the equilibrium constant K for the reaction at 373K can be calculated as follows:
K = [tex]\frac{[CO][Cl_{2}]}{[COCl_{2}]}[/tex] = 2.19×10^{-10}
([X] means = concentration of X)
This means that in the equilibrium the concentration of the reactant (that is in the denominator) will be much higher (around 10^{10} fold) than the concentrations of the products (that are in the numerator), and this means that the equilibrium lies far to the left (to the reactants side) as very small amount of product is being formed.
For the reaction COCl₂(g) ⇌ CO(g) + Cl₂(g), K = 2.19 × 10⁻¹⁰ at 373 K, we can say that the equilibrium lies far to the left (D).
The equilibrium constant (K) is the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to the stoichiometric coefficients.
Let's consider the following balanced equation.
COCl₂(g) ⇌ CO(g) + Cl₂(g)
The equilibrium constant is:
K = 2.19 × 10⁻¹⁰ = [CO] [Cl₂] / [COCl₂]
As we can see, a small value of K means that at equilibrium, there is a bigger amount of reactants than products, that is, the equilibrium lies far to the left.
What can be said about this reaction at this temperature?
(A) The equilibrium lies far to the right. No. This would happen if K were large.
(B) The reaction will proceed very slowly. No. There is no information to speculate about the kinetics of the system.
(C) The reaction contains significant amounts of products and reactants at equilibrium. No. This would happen if K were close to 1.
(D) The equilibrium lies far to the left. Yes. This is due to the small K.
For the reaction COCl₂(g) ⇌ CO(g) + Cl₂(g), K = 2.19 × 10⁻¹⁰ at 373 K, we can say that the equilibrium lies far to the left (D).
Learn more about the equilibrium constant here: https://brainly.com/question/19340344
