Assume we are picking a lottery ticket. We must choose three distinct numbers from 1 to 100 and write them on a ticket. Next, someone picks three numbers one by one from a bowl with numbers from 1 to 100 each time without putting the previous number back in. We win if our numbers are all called in order. If we decide to play the game and pick our numbers as 12, 14, and 89, what is the chance that we win?

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nuuk nuuk · Answer 1 · 2019-10-11T09:33:28+02:00

Answer:0.000103 %

Step-by-step explanation:

Given

there 100 different numbers and someone pick three numbers back to back without putting the previous number back in.

If we pick 12, 14 and 89

Probability to pick 12 in first trail is [tex]\frac{1}{100}[/tex]

Probability to pick 14 in second trail is [tex]\frac{1}{99}[/tex]

Probability to pick 89 in third trail is [tex]\frac{1}{98}[/tex]

thus Probability to win game is =[tex]\frac{1}{100\times 99\times 98}[/tex]

[tex]=\frac{1}{970200}=0.00000103[/tex]

=0.000103 %