Answer:
5.2011 AU
Explanation:
According to the Kepler's Third law
a³ = T²
Here,
a is the distance between the sun and the Jupiter in astronomical units (AU)
and
T is the orbiting period of Jupiter around the sun in years
also,
T = 11.8618 years
Therefore,
The above relation comes as;
a³ = 11.8618²
or
a³ = 140.70
or
a = 5.2011 AU
Hence,
the distance from the Sun to Jupiter is 5.2011 AU