Answer: 0.6881828007
Step-by-step explanation:
Given : The probability of the apples are damaged due to bruising, worms, or other defects : p= 0.11
The sample size : n= 10
Let x be the number of apples are damaged due to bruising, worms, or other defects in the sample.
Using binomial probability formula : [tex]P(x)=^nC_xp^x(1-p)^{n-x}[/tex]
The probability that his sample will contain at least one damaged apple will be :-
[tex]P(x\geq1)=1-P(x=0)\\\\=1-(^{10}C_0(0.11)^0(1-0.11)^{10})\\\\=1-(1)(0.89)^{10}\\\\=1-0.3118171993\\\\=0.6881828007[/tex]
