Answer:
The answer to your question is: ΔHr = - 2598.8 kJ/mol
Explanation:
2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(l)
Enthalpies
C₂H₂(g) = 226.9 kJ/mol
O₂(g) = 0 kJ/mol
CO₂(g) = -393.5 kJ/mol
H₂O(l) = -285.5 kJ/mol
Formula
ΔH r = ∑npHp - ∑nrHp
Process
ΔHr = 4(-393.5) + 2(-285.5) - 2(226.9)
ΔHr = -1574 - 571 - 453.8
ΔHr = - 2598.8 kJ/mol
