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The manufacturer of a 6 V dry-cell flashlight battery says that the battery will deliver 15 mA for 64 continuous hours. During that time the voltage will drop from 6 V to 4 V. Assume the drop in voltage is linear with time. how much energy does the battery deliver in this 64h interval?

Respuesta :

Hania12

Answer:

                                E =17,280 J

Explanation:

Since the voltage drops linearly from 6V to 4V, the average is 5V. The energy delivered is .

V is the average of initial and fianl voltage

A is the current passing

t is the time in which current is passed

               E=V*A*t = 5*0.015*(64*3600) = 17,280 J