Answer:
-13° C
Explanation:
Data provided:
The temperature of the air at sea level = 26° C
The height at which temperature is to be calculated = 6000 m = 6 Km
Now,
Using the average lapse rate
[tex]T_{s+h}=T_s-L_Ph[/tex]
Here,
[tex]T_{s+h}[/tex] is the temperature at the height 'h' above the mean sea level
[tex]T_s[/tex] is the temperature at the mean sea level
[tex]L_P[/tex] is the average lapse rate = 6.5° C per Km
h is the height above mean sea level at which the temperature is to be calculated in Km
on susbtituting the respective values in the above formula, we get
[tex]T_{s+h}[/tex] = 26° C - ( 6.5 × 6 )
or
[tex]T_{s+h}[/tex] = 26° C - 39° C
or
[tex]T_{s+h}[/tex] = -13° C
