A fisherman is fishing from a bridge and is using a "50.0-N test line." In other words, the line will sustain a maximum force of 50.0 N without breaking. What is the weight of the heaviest fish that can be pulled up vertically, when the line is reeled in (a) at constant speed and (b) with an acceleration whose magnitude is 2.98 m/s2?

Respuesta :

Answer:(a) 50 N

(b)38.34 N

Explanation:

Given

Maximum tension(T) in line 50 N

(a)If line is moving up with constant velocity i.e. there is no acceleration

This will happen when Tension is equal to weight of Fish

T-mg=0

T=mg

Maximum weight in this case will be 50 N

(b)acceleration of magnitude [tex]2.98 m/s^2[/tex]

T-mg=ma

[tex]50=m\left ( g+a\right )[/tex]

[tex]50=m\left ( 12.78\right )[/tex]

m=3.91

Therefore weight is [tex]3.91\times 9.8=38.34 N[/tex]