Answer: 446000 Joules
Explanation:
Latent heat of vaporization is the amount of heat required to convert liquid to gas at atmospheric pressure.
Latent heat of vaporization = 2230 J/g
Volume of water = 200 ml
Density of water = 1 g/ml
Mass of water = ?
[tex]Density=\frac{mass}{Volume}[/tex]
[tex]1g/ml=\frac{mass}{200ml}[/tex]
[tex]mass=200g[/tex]
1 gram of water requires energy to evaporate = 2230 Joules
200 gram of water requires energy to evaporate = [tex]\frac{2230}{1}\times 200=446000Joules[/tex]
Thus 446000 Joules of energy is required to evaporate 200 mL of sweat.
